Task and Solution - Re.start() & Re.end() HackerRank

 

start() & end()

These expressions return the indices of the start and end of the substring matched by the group.

Code

>>> import re
>>> m = re.search(r'\d+','1234')
>>> m.end()
4
>>> m.start()
0

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Task
You are given a string .
Your task is to find the indices of the start and end of string  in .

Input Format

The first line contains the string .
The second line contains the string .

Constraints

Output Format

Print the tuple in this format: (start _index, end _index).
If no match is found, print (-1, -1).

Sample Input

aaadaa
aa

Sample Output

(0, 1)  
(1, 2)
(4, 5)

My Solution

import re

target_string = input()

target_find = input()

result = re.findall(target_find, target_string)

store = []

if(result):

    for i in range(len(target_string)):

        if(target_string[i:i+len(target_find)] == target_find):

            store.append(tuple((i,(i+len(target_find))-1 )))

else:

    store.append(tuple((-1,-1)))

for i in store:

    print(i)

Source : HackerRank