A valid email address meets the following criteria:
- It's composed of a username, domain name, and extension assembled in this format:
username@domain.extension
- The username starts with an English alphabetical character, and any subsequent characters consist of one or more of the following: alphanumeric characters,
-
,.
, and_
. - The domain and extension contain only English alphabetical characters.
- The extension is , , or characters in length.
Given pairs of names and email addresses as input, print each name and email address pair having a valid email address on a new line.
Hint: Try using Email.utils() to complete this challenge. For example, this code:
import email.utils
print email.utils.parseaddr('DOSHI <DOSHI@hackerrank.com>')
print email.utils.formataddr(('DOSHI', 'DOSHI@hackerrank.com'))
produces this output:
('DOSHI', 'DOSHI@hackerrank.com')
DOSHI <DOSHI@hackerrank.com>
Input Format
The first line contains a single integer, , denoting the number of email address.
Each line of the subsequent lines contains a name and an email address as two space-separated values following this format:
name <user@email.com>
Constraints
Output Format
Print the space-separated name and email address pairs containing valid email addresses only. Each pair must be printed on a new line in the following format:
name <user@email.com>
You must print each valid email address in the same order as it was received as input.
Sample Input
2
DEXTER <dexter@hotmail.com>
VIRUS <virus!@variable.:p>
Sample Output
DEXTER <dexter@hotmail.com>
Explanation
dexter@hotmail.com is a valid email address, so we print the name and email address pair received as input on a new line.
virus!@variable.:p is not a valid email address because the username contains an exclamation point (!
) and the extension contains a colon (:
). As this email is not valid, we print nothing.
Solution
Source : HackerRank
No comments:
Post a Comment