Task and Solution in Python - Min and Max (HackerRank)

 

min

The tool min returns the minimum value along a given axis.

import numpy

my_array = numpy.array([[2, 5], 
                        [3, 7],
                        [1, 3],
                        [4, 0]])

print numpy.min(my_array, axis = 0)         #Output : [1 0]
print numpy.min(my_array, axis = 1)         #Output : [2 3 1 0]
print numpy.min(my_array, axis = None)      #Output : 0
print numpy.min(my_array)                   #Output : 0

By default, the axis value is None. Therefore, it finds the minimum over all the dimensions of the input array.

max

The tool max returns the maximum value along a given axis.

import numpy

my_array = numpy.array([[2, 5], 
                        [3, 7],
                        [1, 3],
                        [4, 0]])

print numpy.max(my_array, axis = 0)         #Output : [4 7]
print numpy.max(my_array, axis = 1)         #Output : [5 7 3 4]
print numpy.max(my_array, axis = None)      #Output : 7
print numpy.max(my_array)                   #Output : 7

By default, the axis value is None. Therefore, it finds the maximum over all the dimensions of the input array.

---

Task

You are given a 2-D array with dimensions X.
Your task is to perform the min function over axis  and then find the max of that.

Input Format

The first line of input contains the space separated values of  and .
The next  lines contains  space separated integers.

Output Format

Compute the min along axis  and then print the max of that result.

Sample Input

4 2
2 5
3 7
1 3
4 0

Sample Output

3

Explanation

The min along axis  = 
The max of  = 3

Solution

import numpy

n, m = map(int, input().split())

arr = numpy.array([input().split() for i in range(n)], int)

mnarr = numpy.min(arr, axis=1)

mxarr = numpy.max(mnarr)

print(mxarr)

Source : HackerRank